Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). If there is no such window in S that covers all characters in T, return the ...
int res = contiguousStrings(str, i + 1, j, n - 1) + contiguousStrings(str, i, j - 1, n - 1) - contiguousStrings(str, i + 1, j - 1, n - 2); ...
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